OxfordAQA International A Level Chemistry
OxfordAQA International A Level Chemistry 3.3.10 Aromatic Chemistry Exam Questions
Free OxfordAQA International A Level Chemistry revision for 3.3.10 Aromatic Chemistry: what you need to know, common mistakes and exam-style questions with answers. Covers the structure and stability of benzene, nitration, sulfonation, Friedel-Crafts reactions and free-radical chlorination.
Practise 3.3.10 Aromatic Chemistry with past papers
Once you have learnt this topic, find the 3.3.10 Aromatic Chemistry questions in real OxfordAQA International A Level Chemistry past papers and mark them with the mark scheme. Doing lots of real questions is the quickest way to learn how examiners ask about each idea.
About OxfordAQA International A Level Chemistry 3.3.10 Aromatic Chemistry
Aromatic chemistry is an A2 organic topic examined in Unit 4. You need to describe benzene as a planar molecule with delocalised electrons and intermediate bond lengths, and use enthalpies of hydrogenation to explain its extra stability. You also need the mechanisms of electrophilic substitution for nitration, sulfonation and Friedel-Crafts acylation and alkylation using an aluminium chloride catalyst. The OxfordAQA specification also includes free-radical chlorination of benzene, which adds chlorine to the ring, and of methylbenzene, which substitutes into the side chain, and the different reactivity of chlorine attached to a ring or a side chain. It links to amines, dyes and polymers.
What you need to know
- Structure of benzene Benzene is a planar ring of six carbons with a ring of delocalised pi electrons above and below. All the C-C bonds are the same length, between that of a C-C and a C=C bond.
- Stability The enthalpy of hydrogenation of benzene is much less exothermic than three times that of cyclohexene, so benzene is more stable than the Kekulé structure suggests. This is evidence for delocalisation.
- Electrophilic substitution Benzene undergoes substitution rather than addition to keep the stable delocalised ring. The electrophile attacks, forming an intermediate, and loss of H+ restores the ring.
- Nitration and sulfonation Nitration uses concentrated nitric and sulfuric acids to form NO2+, which substitutes onto the ring. Sulfonation introduces an SO3H group.
- Friedel-Crafts reactions Acylation uses an acyl chloride with an AlCl3 catalyst to form an acylium ion, RCO+, giving a phenyl ketone. Alkylation uses a halogenoalkane with AlCl3. AlCl3 is regenerated at the end.
- Free-radical chlorination In UV light chlorine adds to the benzene ring by free-radical addition. With methylbenzene, chlorine substitutes into the methyl side chain. Chlorine on a side chain is more reactive than chlorine attached directly to the ring.
Common mistakes in 3.3.10 Aromatic Chemistry
- Drawing the delocalised ring as a complete circle in the intermediate. In the intermediate the circle is broken into a horseshoe that does not cover the carbon being attacked.
- Saying benzene does not react with bromine because it has no double bonds. It is less reactive because the delocalised electrons have lower electron density than a localised C=C.
- Forgetting to show regeneration of the catalyst, for example H+ + AlCl4- → AlCl3 + HCl.
- Saying benzene undergoes electrophilic addition. It undergoes electrophilic substitution to keep its stability.
Try three 3.3.10 Aromatic Chemistry exam-style questions
1. Write equations to show how the electrophile is formed in the nitration of benzene. (1 mark)
Show the mark scheme answer
HNO3 + 2H2SO4 → NO2+ + H3O+ + 2HSO4- (or HNO3 + H2SO4 → NO2+ + HSO4- + H2O).
2. The enthalpy of hydrogenation of cyclohexene is -120 kJ mol-1 and of benzene -208 kJ mol-1. Calculate the extra stability of benzene compared with the Kekulé structure. (2 marks)
Show the mark scheme answer
Expected for three C=C = 3 x -120 = -360 kJ mol-1; -360 - (-208) = 152 kJ mol-1 more stable.
3. Outline the mechanism for the Friedel-Crafts acylation of benzene with ethanoyl chloride. (4 marks)
Show the mark scheme answer
Formation of CH3CO+ from CH3COCl + AlCl3; curly arrow from delocalised ring to the carbon of CH3CO+; intermediate with horseshoe and positive charge; curly arrow from C-H bond into the ring, losing H+ to give phenylethanone.
3.3.10 Aromatic Chemistry FAQs
What does OxfordAQA International A Level Chemistry 3.3.10 Aromatic Chemistry cover?
It covers the structure and stability of benzene, nitration, sulfonation, Friedel-Crafts reactions and free-radical chlorination.
Which unit is 3.3.10 Aromatic Chemistry examined in?
It is examined in Unit 4, an International A2 paper covering organic and physical chemistry. The Unit 5 practical and synoptic paper can also assess it.
What is the difference between ring and side-chain chlorination?
In UV light, chlorine adds to the benzene ring itself by free-radical addition, but with methylbenzene the chlorine substitutes for hydrogen on the methyl side chain. A chlorine on the side chain is more easily substituted than one on the ring.