Eduqas GCSE Chemistry
Eduqas GCSE Chemistry 9 Rate of Chemical Change and Dynamic Equilibrium Exam Questions
Free Eduqas GCSE Chemistry revision for 9 Rate of Chemical Change and Dynamic Equilibrium: what you need to know, common mistakes and exam-style questions with answers. Covers measuring rates of reaction, collision theory, temperature, concentration, surface area, catalysts, enzymes, reversible reactions and dynamic equilibrium.
Practise 9 Rate of Chemical Change and Dynamic Equilibrium with past papers
Once you have learnt this topic, find the 9 Rate of Chemical Change and Dynamic Equilibrium questions in real Eduqas GCSE Chemistry past papers and mark them with the mark scheme. Doing lots of real questions is the quickest way to learn how examiners ask about each idea.
About Eduqas GCSE Chemistry 9 Rate of Chemical Change and Dynamic Equilibrium
This Eduqas GCSE Chemistry topic covers how fast reactions happen and what happens in reversible reactions. You learn to measure rate by gas collection, mass loss or a colour change, plot and interpret rate graphs, and explain the effects of temperature, concentration, pressure, surface area and catalysts using collision theory. The second part covers reversible reactions, dynamic equilibrium and how changing conditions shifts the position of equilibrium, which leads into the Haber process in topic 11. There are three specified practicals, SP9A, SP9B and SP9C. Examiners often ask you to calculate a mean rate or a gradient and explain changes using collision frequency and activation energy.
What you need to know
- Measuring rate Mean rate = quantity of reactant used or product formed / time, for example cm3/s or g/s. The rate at a point is the gradient of a tangent on the graph. SP9A: effect of one factor on rate using gas collection.
- Collision theory Particles must collide with at least the activation energy. Higher concentration or pressure gives more frequent collisions. Higher temperature makes particles move faster, giving more frequent collisions and a greater proportion with energy above the activation energy.
- Surface area Smaller pieces or powders have a larger surface area to volume ratio, so more particles are exposed and collisions are more frequent. SP9B: effect of one factor on the reaction of dilute hydrochloric acid with sodium thiosulfate, timing until a cross disappears.
- Catalysts and enzymes A catalyst speeds up a reaction without being used up by providing a pathway with a lower activation energy. Enzymes are biological catalysts. SP9C: effect of catalysts such as manganese(IV) oxide on the decomposition of hydrogen peroxide.
- Reversible reactions Some reactions go both ways, shown by a double arrow. If a reversible reaction is exothermic in one direction it is endothermic by the same amount in the other, for example heating hydrated copper(II) sulfate.
- Dynamic equilibrium In a closed system, equilibrium is reached when the forward and reverse rates are equal, so concentrations stay constant. Increasing temperature favours the endothermic direction; increasing pressure favours the side with fewer gas molecules; adding reactant shifts equilibrium towards products.
Common mistakes in 9 Rate of Chemical Change and Dynamic Equilibrium
- Saying particles collide more at higher temperature without mentioning energy. The main reason is that more collisions have energy greater than the activation energy.
- Writing that a catalyst gives particles more energy. It provides an alternative pathway with lower activation energy.
- Saying there are more collisions. Examiners want more frequent collisions, or more collisions per second.
- Saying the reaction stops at equilibrium. Both reactions continue at the same rate; it is a dynamic equilibrium.
- Thinking a catalyst changes the position of equilibrium. A catalyst speeds up both forward and reverse reactions equally, so equilibrium is reached faster but its position is unchanged.
Try three 9 Rate of Chemical Change and Dynamic Equilibrium exam-style questions
1. 60 cm3 of gas was collected in the first 30 s of a reaction. Calculate the mean rate of reaction. (2 marks)
Show the mark scheme answer
Rate = 60 / 30; = 2.0 cm3/s.
2. Explain why increasing the concentration of hydrochloric acid increases the rate of its reaction with magnesium. (3 marks)
Show the mark scheme answer
More acid particles in the same volume; so more frequent collisions with magnesium; more successful collisions per second.
3. N2 + 3H2 ⇌ 2NH3. The forward reaction is exothermic. Predict and explain the effect on the yield of ammonia of increasing the pressure. (3 marks)
Show the mark scheme answer
Yield increases; equilibrium shifts to the right; because there are fewer gas molecules on the right (2 compared with 4).
9 Rate of Chemical Change and Dynamic Equilibrium FAQs
What does Eduqas GCSE Chemistry 9 Rate of Chemical Change and Dynamic Equilibrium cover?
It covers measuring rate, collision theory and the effects of temperature, concentration, pressure, surface area and catalysts, enzymes, reversible reactions and dynamic equilibrium.
Which paper is 9 Rate of Chemical Change and Dynamic Equilibrium examined in?
It is examined in Component 1: Concepts in Chemistry (2 hours 15 minutes, 120 marks). Component 2: Applications in Chemistry can also test it through practical contexts and an unseen article.
How do I find a rate from a graph in Eduqas GCSE Chemistry 9 Rate of Chemical Change and Dynamic Equilibrium?
For a mean rate, divide the total change by the total time. For the rate at a particular time, draw a tangent to the curve and calculate its gradient as change in y divided by change in x, with units such as cm3/s.