Eduqas GCSE Chemistry
Eduqas GCSE Chemistry 11 Production, Use and Disposal of Important Chemicals and Materials Exam Questions
Free Eduqas GCSE Chemistry revision for 11 Production, Use and Disposal of Important Chemicals and Materials: what you need to know, common mistakes and exam-style questions with answers. Covers the Haber process, fertilisers, percentage yield, atom economy, corrosion and its prevention, alloys, choosing materials, life cycle assessment and recycling.
Practise 11 Production, Use and Disposal of Important Chemicals and Materials with past papers
Once you have learnt this topic, find the 11 Production, Use and Disposal of Important Chemicals and Materials questions in real Eduqas GCSE Chemistry past papers and mark them with the mark scheme. Doing lots of real questions is the quickest way to learn how examiners ask about each idea.
About Eduqas GCSE Chemistry 11 Production, Use and Disposal of Important Chemicals and Materials
This Eduqas GCSE Chemistry topic applies earlier chemistry to industry and sustainability. You study the Haber process and the compromise conditions chosen, how ammonia is used to make NPK fertilisers, and how to calculate percentage yield and atom economy. It also covers rusting and how to prevent it, alloys such as steel and brass, choosing materials from their properties, life cycle assessments and recycling. SP11 measures the percentage of water in a hydrated salt. The topic draws on equilibrium (topic 9), moles (topic 3) and metals (topic 6). Examiners often ask you to justify the Haber process conditions, calculate yield or atom economy, and evaluate a life cycle assessment.
What you need to know
- Haber process N2 + 3H2 ⇌ 2NH3, forward reaction exothermic. Typical conditions: about 450 °C, about 200 atmospheres and an iron catalyst. A lower temperature would give a higher yield but too slow a rate; higher pressure would increase yield but costs more and is less safe. Unreacted gases are recycled.
- Fertilisers NPK fertilisers supply nitrogen, phosphorus and potassium for plant growth. Ammonia is used to make nitric acid and ammonium salts such as ammonium nitrate and ammonium sulfate.
- Yield and atom economy Percentage yield = (actual mass / theoretical mass) x 100. Atom economy = (Mr of desired product / total Mr of reactants) x 100. A high atom economy means less waste and is more sustainable.
- Corrosion Rusting needs both water and oxygen. It is prevented by barriers (paint, oil, plastic), galvanising with zinc, or sacrificial protection, where a more reactive metal corrodes instead of the iron.
- Alloys and materials Alloys are harder than pure metals because different sized atoms disrupt the layers so they cannot slide. Steel, brass and bronze are common alloys. Materials are chosen by properties such as strength, density, conductivity and cost.
- Life cycle assessment and SP11 A life cycle assessment considers raw materials, manufacture, use and disposal. Reduce, reuse and recycle conserves resources and energy. SP11: heat a hydrated salt such as copper(II) sulfate to constant mass to find the percentage of water.
Common mistakes in 11 Production, Use and Disposal of Important Chemicals and Materials
- Saying 450 °C is used because it gives the highest yield. It is a compromise between an acceptable yield and a fast enough rate.
- Confusing percentage yield with atom economy. Yield compares actual and theoretical product; atom economy compares the mass of desired product with all products from the equation.
- Saying galvanising works only as a barrier. Zinc is also more reactive than iron, so it corrodes sacrificially even if scratched.
- Stating that alloys are harder because they are stronger metals. Explain that different sized atoms distort the layers so they cannot slide.
- Heating a hydrated salt once only. Heat to constant mass so that all the water has been removed.
Try three 11 Production, Use and Disposal of Important Chemicals and Materials exam-style questions
1. A reaction has a theoretical yield of 34 g but only 25.5 g of product is obtained. Calculate the percentage yield. (2 marks)
Show the mark scheme answer
Percentage yield = 25.5 / 34 x 100; = 75%.
2. 2.50 g of hydrated copper(II) sulfate, CuSO4.xH2O, was heated to constant mass, leaving 1.60 g of anhydrous CuSO4. Calculate the percentage of water and the value of x. (Mr: CuSO4 = 159.5, H2O = 18) (4 marks)
Show the mark scheme answer
Mass of water = 2.50 - 1.60 = 0.90 g, so % water = 0.90 / 2.50 x 100 = 36%; moles CuSO4 = 1.60 / 159.5 = 0.0100; moles H2O = 0.90 / 18 = 0.050; ratio 1:5 so x = 5.
3. Explain why a pressure of about 200 atmospheres is used in the Haber process rather than a much higher pressure. (3 marks)
Show the mark scheme answer
Higher pressure would increase the yield because there are fewer gas molecules on the product side; but very high pressure is expensive to produce / needs stronger equipment; and is more dangerous, so 200 atmospheres is a compromise.
11 Production, Use and Disposal of Important Chemicals and Materials FAQs
What does Eduqas GCSE Chemistry 11 Production, Use and Disposal of Important Chemicals and Materials cover?
It covers the Haber process and fertilisers, percentage yield and atom economy, corrosion and its prevention, alloys and choosing materials, life cycle assessments, recycling and the water in hydrated salts.
Which paper is 11 Production, Use and Disposal of Important Chemicals and Materials examined in?
It is examined in Component 1: Concepts in Chemistry (2 hours 15 minutes, 120 marks). Component 2: Applications in Chemistry can also test it through practical contexts and an unseen article.
What should I know about the Haber process for Eduqas GCSE Chemistry 11 Production, Use and Disposal of Important Chemicals and Materials?
Learn the equation, the raw materials (nitrogen from the air and hydrogen from natural gas), the conditions with reasons for each, the role of the iron catalyst and why unreacted gases are recycled.