AQA A Level Chemistry
AQA A Level Chemistry 3.1.8 Thermodynamics Exam Questions
Free AQA A Level Chemistry exam questions for 3.1.8 Thermodynamics, with a mark scheme for every pack. Covers Born-Haber cycles, lattice enthalpies, enthalpies of hydration and solution, entropy changes, Gibbs free energy and feasibility of reactions.
3.1.8 Thermodynamics exam questions
1 question pack of real past exam questions, each with its mark scheme. Do not stop after a few: answer as many as you can without notes, then mark every answer with the mark scheme. The more questions you do, the more quickly you will spot how examiners ask about each idea.
About AQA A Level Chemistry 3.1.8 Thermodynamics
Thermodynamics is the A Level extension of energetics. On the AQA course you construct Born-Haber cycles to calculate lattice enthalpies, compare experimental values with those from a perfect ionic model to judge covalent character, and use cycles of enthalpies of solution and hydration. You also meet entropy as a measure of disorder, calculate entropy changes, and use the Gibbs free energy equation ΔG = ΔH - TΔS to decide whether a reaction is feasible and to find the temperature at which it becomes feasible. Examiners test precise definitions, multi-step cycle calculations, unit conversion between J and kJ, and graphs of ΔG against temperature.
What you need to know
- Key definitions Enthalpy of lattice formation: the enthalpy change when one mole of a solid ionic compound is formed from its gaseous ions (exothermic). Lattice dissociation is the reverse (endothermic). Enthalpy of atomisation: the enthalpy change when one mole of gaseous atoms is formed from the element in its standard state.
- Electron affinity First electron affinity is the enthalpy change when one mole of gaseous atoms each gain one electron to form one mole of gaseous 1- ions, and is exothermic. The second electron affinity is endothermic because an electron is added to a negative ion, which repels it.
- Born-Haber cycles The enthalpy of formation equals the sum of atomisation enthalpies, ionisation energies, electron affinities and the lattice formation enthalpy. Rearrange the cycle to find any unknown term.
- Perfect ionic model Theoretical lattice enthalpies assume spherical ions with only ionic bonding. If the Born-Haber value is more exothermic than the theoretical one, the compound has some covalent character caused by polarisation of the anion.
- Solution and hydration Enthalpy of solution = lattice dissociation enthalpy + sum of the enthalpies of hydration of the ions. Hydration is more exothermic for smaller, more highly charged ions.
- Entropy Entropy, S, measures disorder and has units of J K-1 mol-1. Gases have much higher entropy than liquids and solids. ΔS = sum of S(products) minus sum of S(reactants).
- Gibbs free energy ΔG = ΔH - TΔS. A reaction is feasible when ΔG is less than or equal to zero. Setting ΔG = 0 gives the temperature at which it becomes feasible, T = ΔH / ΔS, with ΔS converted to kJ K-1 mol-1.
Common mistakes in 3.1.8 Thermodynamics
- Mixing units in ΔG = ΔH - TΔS. Entropy is usually given in J K-1 mol-1 and must be divided by 1000 before combining with ΔH in kJ mol-1.
- Giving the second electron affinity a negative sign. It is endothermic because the incoming electron is repelled by the negative ion.
- Using the bond enthalpy of Cl2 for the atomisation of chlorine. Atomisation forms one mole of Cl atoms, which is half the bond enthalpy.
- Assuming a feasible reaction will happen quickly. A large activation energy can make a feasible reaction too slow to observe.
- Explaining the difference between theoretical and experimental lattice enthalpies without mentioning polarisation and covalent character.
Try three 3.1.8 Thermodynamics exam-style questions
1. Calculate the enthalpy of lattice formation of sodium chloride. ΔfH(NaCl) = -411, atomisation of Na = +107, atomisation of Cl = +122, first ionisation energy of Na = +496, first electron affinity of Cl = -349, all in kJ mol-1. (2 marks)
Show the mark scheme answer
ΔLfH = ΔfH - (107 + 122 + 496 - 349); = -411 - 376 = -787 kJ mol-1.
2. For CaCO3(s) → CaO(s) + CO2(g), ΔH = +178 kJ mol-1 and ΔS = +161 J K-1 mol-1. Calculate the minimum temperature at which the reaction is feasible. (2 marks)
Show the mark scheme answer
At ΔG = 0, T = ΔH / ΔS; T = 178 / 0.161 = 1110 K (1106 K).
3. The experimental lattice enthalpy of silver iodide is more exothermic than the value calculated using the perfect ionic model. Explain this difference. (2 marks)
Show the mark scheme answer
The Ag+ ion polarises the large iodide ion, distorting its electron cloud; so the bonding has some covalent character, which makes the lattice stronger than predicted for purely ionic bonding.
3.1.8 Thermodynamics FAQs
What does AQA A Level Chemistry 3.1.8 Thermodynamics cover?
It covers Born-Haber cycles, lattice enthalpies and the perfect ionic model, enthalpies of solution and hydration, entropy changes and Gibbs free energy, including when reactions become feasible.
Which paper is 3.1.8 Thermodynamics examined in?
It is examined in Paper 1, and Paper 3 can also test it.
What is the best way to revise Born-Haber cycles?
Learn every definition, then practise drawing full cycles with arrows going up for endothermic steps and down for exothermic ones. Check whether each step is per mole of atoms or ions, especially for compounds such as MgCl2 that need two moles of chlorine atoms.